Question

15. -/3 points OSColPhys2016 30.3.WA.017. If a hydrogen atom is in the n = 12 state, determine the following (in eV). total energy of the atom kinetic energy of the electron potential energy of the atom ev

Answer 1

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TOTAL ENERGY:

We know that the total energy of the hydrogen atom is given by,

$E_{total}=\frac{-13.6\;eV}{n^{2}}=\frac{-13.6\;eV}{(12)^{2}}$

$\mathbf{E_{total}=-0.094\;eV}$

KINETIC ENERGY:

We know that the kinetic energy of the electron in hydrogen atom is given by,

$\mathbf{K.E=-E_{total}=+0.094\;eV}$

POTENTIAL ENERGY:

We know that the potential energy of the electron in hydrogen atom is given by,

$P.E=2\timesE_{total}=2\times-0.094\;eV$

$\mathbf{\therefore P.E=-0.189\;eV}$