Question

Find the critical value t for the confidence level c = 0.99 and sample size n=9. - Click the icon to view the t-distribution table. (Round to the nearest thousandth as needed.)

Answer 1

Solution :

Given that,

sample size = n = 9

Degrees of freedom = df = n - 1 = 9 - 1 = 8

At 99% confidence level

$\alpha$ = 1 - 99%

$\alpha$ =1 - 0.99 =0.01

$\alpha$/2 = 0.005

t$\alpha$/2,df = t _{0.005, 8} = 3.355

t_c = 3.355