Question

Preview File Edit View Me %38 D Mon 12:30 Q Go Tools Window Help phys104 lab final 2020.pdf (page 3 of 4) e 1 * ® Q Search Öğrenci İşlemlari: Kontrol panell 31 Fig... 9V 20 20 10 2V Fig. 1 Fig. 2 31 Fig... White Noa 2 lease. Thank you 5) (10p) Calculate the magnetic flux density at the center of the coil (B(0)) according to the values given in the table: (Magnetic field constant u, = 1.2566 * 10 H/m) n 1(mm) R Blo)(mt) lease. Thank you Measured Calculated 75 160 13 0.56 150 160 13 1.14 300 160 13 2.27 own in Fig. P6.27 Figure P6.27 d the pulse duration is 0.24 a machine operating at 468 e power and (d) peak power WE AN * JI A WE

Answer 1

m = Here, Number of turns →n=75 Current in the coil + 1 = 160 mA = 160 x 10-3 A Radius of the coil R= 13 mm = 13 x 10-3 Permeability of space + HO = 1.2566 x 10-6 H/m The magnetic flux density B is given by: Hon B 2R 1.2555 x 10-6 x 75 x 160 2 x 13 :: B = 0.58 mT The percentage difference can be calculated as: B % difference = calculated – measured calculated x 100% B B % difference = 0.58 – 0.56 0.58 x 100% B% difference = 3.448%

Here, Number of turns →n= 150 Current in the coil + 1 = 160 mA = 160 x 10-3 A Radius of the coil R= 13 mm = 13 x 10-3 m Permeability of space + Ho = 1.2566 x 10-6 H/m B Mon ) 2R 1.2555 x 10-6 x 150 x 160 2 x 13 ..B = ..B= 1.16 mT The percentage difference can be calculated as: calculated – measured B% difference = calculated X 100% B % difference = 1.16 – 1.14 1.16 x 100% B% difference = 1.724%

Here, Number of turns →n=300 Current in the coil + 1 = 160 mA = 160 x 10-3 A Radius of the coil → R= 13 mm = 13 x 10-3 m Permeability of space + Mo = 1.2566 x 10-6 H/m The magnetic flux density B is given by: Mon ) B = 2R 1.2555 x 10-6 x 300 x 160 2 x 13 B = B = 2.32 mT The percentage difference can be calculated as: calculated – measured B% difference = calculated x 100% B% difference = 2.32 – 2.27 2.32 X 100% B% difference = 2.155%