Question

Assume the random variable X has a binomial distribution with the given probability of obtaining a success. Find the following probability, given the number of trials and the probability of obtaining a success. Round your answer to four decimal places. P(X 11), n= 18, p = 0.6

Answer 1

The required probability is

$P(X=11)=\binom{18}{11}(0.6)^{11}(1-0.6)^{18-11}=31824 \cdot 0.6^{11}\cdot 0.4^{7}=0.1892$

Answer: 0.1892