Question

Two 120V light bulbs, one 25W and one 200W, were connected in series across a 240V line. It seemed like a good idea at the time, but one bulb burned out almost instantaneously. Which one burned out, and why?

Answer 1

solno voltage of both bulbs, V = 120 volts. Power of and bulb, pe = 25 w Power of other bulb, P2 - 200 W P- V? - 1576 ohm For bulb Ri=v² = (120) P, а на 25 and since p =VI Therefore, VI, =v² Sš = [0.2084 For bulb 2 R2 = V2 2 - (120)2 200 = 172 ohm and and I2 = v = 120 = 1.67A) 12o R2 22

When both bulb connected in series across a 240 u totul Resistance will be = 576+72 R = RltR2 [R = 6480 / Total G current = V R in - I the circuit 240 640 I = 0.370 A since bulb with value of current circuit. Therefore power 25 w have smaller than the current in the it burned out furste