A 31.0 g wire of length L= 0.62 m suspended by a pair of flexible leads...
A 31.0 g wire of length L= 0.62 m suspended by a pair of flexible leads in uniform magnetic field of magnitude 0.5 T. What are the magnitude and direction of the current required to move the tension in supporting leads?
Homework Answers
F = Bil
mg = Bil
i = mg / Bl
= (31*10^-3)(9.8) / (0.5)(0.62)
= 0.98 A
Based on the Right hand rule the current must go Counter Clock Wise, so i flows to right side.
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A horizontal length of current-carrying wire is suspended from two identical flexible leads that are under tension due to the weight of the wire. The wire is oriented at right angles to a uniform magnetic field that has a magnitude of 3 T and is directed into the screen of the figure. The length L of the wire is 5 cm and its mass m is 10 g. What current will produce a magnetic force on the wire such that...
A horizontal length of current-carrying wire is suspended from two identical flexible leads that are under...
A horizontal length of current-carrying wire is suspended from
two identical flexible leads that are under tension due to the
weight of the wire. The wire is oriented at right angles to a
uniform magnetic field that has a magnitude of 4 T and is directed
out of the screen of the figure. The length L of the wire is 5 cm
and its mass m is 10 g. What current will produce a magnetic force
on the wire that...
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two identical flexible leads that are under tension due to the
weight of the wire. The wire is oriented at right angles to a
uniform magnetic field that has a magnitude of 4.5 T and is
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is 5 cm and its mass m is 10 g. What current will produce a
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