SOLUTION:-
Null to null bandwidth = + RHZ
= bit rate
= 38.4 KHZ
The PSD of NRZ polar line coding with equally likely bits is given
by
![S(f)=V^{2}T\left [ \frac{sin \Pi FT}{\Pi FT} \right ]^{2}](http://img.homeworklib.com/questions/00d303a0-d491-11ea-9fe4-a19533431d73.png?x-oss-process=image/resize,w_560)
When the probability of 1 is P, and O is not 0.5, a dc component exists and the PSD becomes
![S(f)= 4V^{2}TP(1-P) \left [ \frac{Sin \Pi FT}{\Pi FT} \right ]^{2}+V^{2}(1-2P)^{2}\delta(F)](http://img.homeworklib.com/questions/012bbc00-d491-11ea-bc02-c144dfc46372.png?x-oss-process=image/resize,w_560)
Note:- +1
+V volts }
0
-V volts } representation for NRZ
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(4 points) The RS-232 port on a PC transmits data at 38.4 kbps using polar NRZ...