Question

write c++ code to read two complementary complex numbers and output their multiplication and division using separate functions. Print each of the values in the form a+ib or a-ib. Write C++ program and write algorithm in words for the problem. Note: A complex number a +ib has complementary complex number a-ib.

Answer 1

Please find the code below:::

main.cpp

#include<iostream>
#include<cmath>
using namespace std;

class complex
{
private:
   float rel;
   float img;
public:
   complex(float relIn,float imgIn){
       rel = relIn;
       img = imgIn;
   }
   complex(){
       rel = 0;
       img = 0;
   }
   complex operator *(complex s2){
       float a,b;
       a=((rel)*(s2.rel))-((img)*(s2.img));
       b=((rel)*(s2.img))+((s2.rel)*(img));
       return complex(a,b);
   }

   complex operator /(complex s2){
       float a,b;
       float part = s2.rel*s2.rel +s2.img*s2.img;
       a = (rel*s2.rel + img*s2.img)/part;
       b = (img*s2.rel - rel*s2.img)/part;
       return complex(a,b);
   }

   void print(){
       cout<<rel;
       if(img>=0){
           cout<<"+"<<img<<"i"<<endl;
       }else{
           cout<<img<<"i"<<endl;
       }
   }
};

int main()
{
   float real,img;
   cout<<"Enter real part of complex number : ";
   cin>>real;
   cout<<"Enter imaginary part of complex number : ";
   cin>>img;

   complex num1(real,img);
   complex num2(real,-1*img);

   cout<<"Numer1 : ";num1.print();
   cout<<"Numer2 : ";num2.print();
   complex mul =num1*num2;
   cout<<"Multiplication : ";mul.print();

   complex div =num1/num2;
   cout<<"Division : ";div.print();

   return 0;
}

output:

모 Console X くterminated> CPP Workspace.exe [C/C++ Application] C:NUsers Mohammad Shah Enter real part of complex number 1 Enter imaginary part of complex number : 12 Numerl 1+12i Numer2 : 1-12i Multiplication 145+0i Division: -0.986207+0.1655171