Question

A Review Constants Part B From the six diagrams shown below, choose three correct diagrams that show the spheres (i) before the first collision, (ii) after the first collision but before the second collision, and (iii) after the second collision. Do not perform any calculations and use only the information given in the introduction. Drag the appropriate labels to their respective targets. Three targets should be left blank. Sphere A, of mass 0.600 kg, is initially moving to the right at 4.00 m/s. Sphere B, of mass 1.80 kg, is initially to the right of sphere A and moving to the right at 2.00 m/s. After the two spheres collide, sphere B is moving at 3.00 m/s in the same direction as before. (a) What is the velocity (magnitude and direction) of sphere A after this collision? (b) Is this collision elastic or inelastic? (c) Sphere B then has an off-center collision with sphere C, which has mass 1.60 kg and is initially at rest. After this collision, sphere B is moving at 19.0° to its initial direction at 1.40 m/s. What is the velocity (magnitude and direction) of sphere C after this collision? (d) What is the impulse (magnitude and direction) imparted to sphere B by sphere C when they collide? (e) Is this second collision elastic or inelastic? () What is the velocity (magnitude and direction) of the center of mass of the system of three spheres (A, B, and C) after the second collision? No external forces act on any of the spheres in this problem. View Available Hint(s) Reset Help B C B(iii) x ------ +x VBO cm = 0 A 19° +x В --- = ? Г ---- +x A(un) ? ? Cli B(i) B + ... +x VB B ..... A U +x A = ? .. +x = ? ? 4() c como Am=? (iii)

Please label ON the diagram as i,ii,iii

Answer 1

Since we don't have to perform any calculation on the paper but we will have to perform calculation in the mind itself because we know that in the collision and momentum remains conserved therefore initial momentum must be equal to final momentumm therefore according to the data given in the questionThink about momentum um is a amis o,6 % % Pi = (0.6 x 4)+(1.8 x 2) = 6 Since initial momentum is in the right direction therefore final momentum must also be in the right direction and be equal in magnitude 1. imis 3mls 0,6 kg Pr = (0.6 x 1) + (1.8 x 3) = 6 According to the data given in the question momentum of B is 5.4 which is less than 6 therefore to have net momentum equal to 6 in the right direction A must also have momentum in the right direction therefore A will be having velocity in the right direction after first collision Now when sphere B collides with sphere C net momentum of the system for B and sphere C system is in the right direction and spheres B makes an angle 19° with the positive direction of X axis therefore it will have some momentum in the y direction therefore to cancel the momentum of a sphere B in the y direction sphere C must also have some momentum in the y direction hence sphere c moves at an angle below X axis after

collision Therefore correct sequence of the diagrams is OB BOC ic=0 VBO 1900 C .. + Aci) = ? (1) ? Ver Pow) = 0 ВА +y Bm VO D A B (812 C U .... +x | =0 () O ccm) = ?