1)
Metals donate electrons. Once it donate electron metals become
positively charged
ions .They are called cations
2)
Non metals accept electrons.They become negatively charged ions
called
anions
3)
use formula 2n^2 to get number of electrons in each
shell,where
n= number of shell
for 1stshell n=1; so 2n^2=2
Thus first shell can have maximum 2 electrons
for 2nd shell ;n=2 thus
2n^2 = 8
Thus second shell can have maximum 8 electrons
for 3rd shell ;n=3 thus
2n^2 = 18
Thus third shell can have maximum 18 electrons
4) For a stable atom valance shell should have 8 electrons
***********
Ionic bond
Na :atomic number,Z =11
So number of protons = Z= 11
Number of electrons in Na atom= 11
electron configuration : 2,8,1
# of electrons in 1st shell =2
# of electrons in 2nd shell = 8
# of electrons in 3rd shell =1
**********
Cl :atomic number Z= 17
number of protons = 17
number of electrons = 17
electron configuration : 2,8,7
# of electrons in 1st shell =2
# of electrons in 2nd shell = 8
# of electrons in 3rd shell =7
***********
Na donate 1 electron while forming NaCl :SO Na is a metal
Cl accept one electron while forming NaCl: So Cl is a non
metal
*********
Example 2
Hydrogen :atomic number ,Z=1
So number of protons = Z= 1
Number of electrons in H atom= 1
electron configuration : 1
# of electrons in 1st shell =1
# of electrons require to fill up 1st shell =1
Oxygen :Atomic number ,Z=8
So number of protons = Z= 8
Number of electrons in Na atom=8
electron configuration : 2,6
# of electrons in 1st shell =2
# of electrons in 2nd shell = 6
# of electrons oxygen need to fill up 2nd shell = 2
*********
In water molecule O-H bond is polar due to the electronegativity
difference
between O and H atom .So shared electrons will slightly shift
towards O atom
Thus O atom will get Partial negative charge
And H atom will have partial positive charge
****************
Thank you >All solved :))
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