Question

A slip for tape casting contains, on a weight basis, 100 parts Al₂O₃, 10 parts nonvolatile organic, and 35 parts toluene. After drying, the adherent tap is 60% of the original thickness of the cast. Estimate the porosity of the tape after drying and after binder burnout. Assuming the nonvolatile organic has 1 g/cc density, all the organics are removed and no tape shrinkage occurs during binder burnout.

Answer 1

som Pжкоме #алла алды он: 100g Al2O3 log non volatie Organic 35 9 τοιυεου Aften drying an toluene is removed; Wdry= nog Aften buren off , an of the non vaatre organice is removed. Wburen = 100g 60% thickness if left after drying, which Means 40% vaume i loss due to Toluene evaporation. ftoivene = 0.87 9/6 volume of toluene : 359 10.889 lec = 42-200 wet volume = 42.2 0/0.4 = 105.5 Vory = 0.6 (103.560) - 63:3 CC Vdrys Vsoud + Vrood Since non volante fraction is small and Coats AL203 , A safe to assume CAL203 + non volanie organics) has the density of 3.95

Vsou'd = "og/3959/4c = 278 cc porosity after drying = V void /vary -(63-300-27.822). 0.56 63-3 cc safe to anume 1. Uburn = V day as there is no densification in this step .. Vsolid = 100g /3.959/6= 25.36 porosing often burn off = Vvoid Vsould -63.316 - 253cc) 63.3cc Porosity aften burn off = 0.60 . Hope This Helps. Thank You. Thumbs Up Please.