Question

Primary Visible Occurs emissions at 463 nm. Calculate the energy of a single the 1 One of 447 nm. primary Visible emissions occurs at a mole of Calculate Photons of the th ess a w aveler 1 Microwave ras of 1.8cm. Calculate and the eneran the frequency : - Frequency Energy : Calculate number of the Photons

Answer 1

Q1)

Solution-

Wavelength of light = 463 nm = 463 x 10-9 m

A photon of electromagnetic radiation possesses an energy expressed by:

E = hc / λ , where λ is its wavelength, and h, c are the Planck constant and the speed of light, respectively.

Therefore,

Energy of a single photon of this emission, E =(6.62607 x 10-34) x ( 3 x 108) /(463 x 10-9)

  = 4.293349 x 10-19 J

Q2)

Solution-

Wavelength of light = 447 nm = 447 x 10-9 m

A photon of electromagnetic radiation possesses an energy expressed by:

E = hc / λ , where λ is its wavelength, and h, c are the Planck constant and the speed of light, respectively.

Therefore,

Energy of a single photon of this emission, E =(6.62607 x 10-34) x ( 3 x 108) /(447 x 10-9)

  = 4.44703 x 10-19 J

Energy of a mole of these photons = avogadro number x energy of 1 photon

=(6.022 x 1023) x 4.44703 x 10-19

= 267800.1466 J

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