Degree of dissociation(x) = 1/100 = 0.01
C = concentration of NH4OH = 0.01 M
NH4OH - WEAK base
[OH-] = CX
= 0.01*0.01
= 1*10^-4 M
pOH = -log(OH-)
= -log(1*10^-4)
= 4
pH = 14-pOH
= 14-4 = 10
[H3O+] = 10^-10
From 1.0 M NH4OH and 1.0 M NH4Cl reagent stock solutions prepare
100 mL of the solutions described in the table and complete the
table.
Volume NH3 Volume NH4+ Solução [NH3]/[NH4+][NH3] + [NH4+] 1:1 0,10 1:1 0,20 1:10 0,20 10:1 0,20
From 1.0 M NH4OH and 1.0 M NH4Cl reagent stock solutions prepare
100 mL of the solutions described in the table and complete the
table.
*STEP BY STEP*
Volume NH3 | Volume NH4+ [NH3]/[NH4] [NH3] + [NH4] 1:1 0,10 1:1 0,20 0,20 1:10 10:1 0,20
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A solution is 0.010 M in HCl and 0.010 M in NH4Cl. What is the molar concentration of NH3 at equilibrium? Kb(NH3) = 1.8 x 10-5 (Please explain the process in depth if possible)
You need to prepare 200 mL of a 0.4 M solution of ammonium hydroxide (NH4OH) You have 80 mL of a 0.5 M NHOH solution and 40 mL of a 7.5% (w/v) NH4OH solution. What volume of 7.5% NHOH and water needs to be added to the 80 mL of 0.5 M NH4OH solution to make up 200 mL of 0.4 M NH4OH? Molar mass of NH4OH 35.04 g/mol % (weight / volume) means mass (in g) in volume (100...
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Prepare a series of 50 mL quinine standard solutions (10, 1.0, 0.10, 0.010, 0.0010μg/mL) by serial dilutionfrom the 100 μg/mL stock solution using0.05 M H2SO4as the diluent.
A solution contains 0.60 M NH4OH and 1.50 M NH4Cl. What is the maxiumum concentration of Mg2+ that can be present in such a solution without precipitating Mg(OH)2? (Ksp for Mg(OH)2 = 9.0 x 10^12; Kb fro NH4OH= 1.8 x 10^-5)
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