Two Train Whistles from trains
A and B have the same frequency of 180hz......
Answers should be 3.79m/s and 3.88m/s
Thanks in advance
The beat frequency equals the absolute value of the difference
between the two source frequency, or :
f(b) = |f₂ - f₁|
This allows for two different frequencies, one for approach and one
for recession. The approach frequency is :
2.00Hz = |180Hz - f₁|
2.00Hz = f₁- 180Hz
f₁= 182Hz
The recession frequency is :
2.00Hz = |180Hz - f₁|
2.00Hz = 180Hz - f₁
f₁= 178Hz
Now, from the Doppler shift equation, the approach velocity is
:
f₀ = f(s)[v / v + v(s)]
v(s) = v[f₀ - f(s)] / f₀
= 345m/s[178Hz – 180Hz] / 180Hz
= 3.79m/s
The velocity of recession is (from the same equation) :
v(s) = 345m/s[178Hz - 180Hz] / 178Hz
= -3.88m/s
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