Question

Knowing the Latimer diagram of Ea for Cl as follows:

1.20 1.18 1.19 1.70 1.63 1.36

Ea ClO4- －→ ClO3- －→ ClO2 －→ HClO2 －→ HClO- －→ Cl2 －→ Cl-

(a) Construct the Latimer diagram of Eb for Cl.

(b) What species are expected in the acid and base solutions of Cl2, and why?

Answer 1

| @ clo, 1-2v, q10, 118 119 132 Helo c,1. 136 V Latimer diagram: For 0.5.(-1) : [C1 (N=-1)] 0.5.- oxidation NE'- nie =(-1) X1.36 = -1.360 state For o.s. (0): [cl (N= 0)] NE°- n, Ei = 0x1136 = 0 For 0.5.(1): [HC10/C12 (N = 1) ] NE° = nie; = 1.163 v For 0.5.(111) : [2102/C12 (N=3)] NE° = nie , tn, E° = 1 x 1.163 + 2x1.70 = 4.563 v For 0.5 (v): [1103/c12 (N=6)] - NE" = n, Ei+ n2 E q + nz E ₂ = = 6.923 V For 0.5 (v11) : [c105/19 (N = 7)] NE' = nie,' + m2 E,' + 1 X 1.163 + 2 X 1.70+ 2x 1:18 1:20 1 x 1, 163 + 2x 1.70 + 2X1. 18+ 2 9.323 V

€ Latimen diagram - NE - oxidation state →

- 1 7oV clo for Hero los cl we get the portion of and part Helo "1635 els jies 2 He10084 24+ +re - C1967 2 H70 ... E = E° +00059 x 2log [+]+ 0.059 log = 8° +01059 log [#] - Eº - 0.05a P1 0.059 ' E - EO 2 In acid medium, PHLE, in E = E°- 0.059 pH <7 - 1.163 -0.059 pH <7 = o we value so, E-value is lower than Encio so, Helo converted in to ch but ClO₂- not converted Coxidized) into Helo, In base medium , pH 77 So, in E = EP-0.059 pH > 7 = 0 ve value E-value is higher than E²4 10/cl. does not oxidized into clai So, Helo