Question

Wet product Mass = 400kg Water Mass = 320kg. Temprature = SOC Solid mass = Boky. M=? Humidity Ratio: 0.017kg DRIER Rhz ? Relative hum: 5.7% Enth 22 Euthlapy = 10.7285 Mass = 90 kg Specific Volume water mass= lokg. Speglie Volume = 102m3 Solid mass 2 Soka ng V DRY Product Water Removal rate : 44.26 kq

I am trying to figure out the mass flow rate of air required to dry 310 kg of water from the product.

Answer 1

Assumption: It air got satubiled after paring through drier then at 80's its relative humility ratio for exit air (saturated) 0.353 de Alchange) in water condent -0.353-0017 kg «0-336 kg eg Required water mass taken by air=310 kg or Renoval rate : 4428 kg So man flow rate required is in atein 10.336) a nuzer koster ni - 4428 0.336 - 13x10° kg/or laire) Assumption - air temperature is not changing = 802 final en 100% Enthalpy 152621 koleg so I