Question

Assume that the average water bill is $15.30 with standard deviation $4.10. a) What is the...

Assume that the average water bill is $15.30 with standard deviation $4.10.
a) What is the probability that in a random sample of 36 people in a particular neighborhood
their average water bill is $14.00 or less.
b) What is the smallest range of water bill amounts covering 99% of the distribution?
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Answer #1

Solution Given that, u= 15.30 6 - 4.10 n = 36 Mx = 1= 15.30 P (*<14.00) -Pfalt < 150 1530) -P(Z <= 132 ) – P(Z <-1.91) P(x<19b) The 2 distribution of the 99% is P(Z <z) = 99% P(Z < 2 ) = 0.99 P(Z <2.33) = 0.99 Z = 2:33 2 score formulla X - Zot u x =

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