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0 A)Cold work generally lead to the following changes in a metal A. change in grain...
Use the following key words for part I: Forging Solid Solution Alloying Rolling Grain Size Reduction...
Use the following key words for part I: Forging Solid Solution Alloying Rolling Grain Size Reduction Strain Hardening Extrusion I- Among the given key words: a) (3) Provide ALL techniques for cold working. b) (5) Provide ALL methods for material strengthening. In one sentence, explain how all these methods provide material strengthening. c) (2) Which method provides material strengthening by increasing the grain boundary surface? d) (2) Which method provides material strengthening by increasing the amount impurity atoms? e) (2)...
Q-12. Which stage of the annealing of a cold worked metal causes the strength and grain...
Q-12. Which stage of the annealing of a cold worked metal causes the strength and grain size to decrease? (a) Grain growth (b) Recrystallization (c) Recovery Q-13. What is termed a "stress-relief anneal” is achieved as a result of (a) Recovery (b) Recrystallization (c) Grain growth Q-14. During recovery, we expect all of the following EXCEPT (a) Residual stresses to be reduced or eliminated (b) Electrical conductivity to increase (c) The anisotropic behavior caused by cold working to be eliminated...
Q-1. You are testing a circular beam of two metals, 1045 steel and 2014-T6 aluminum, in...
Q-1. You are testing a circular beam of two metals, 1045 steel and 2014-T6 aluminum, in a rotating-cantilever beam fatigue test. If you need to choose one of these metals so that you can essentially design a part made of that metal, and subject the part to a repetitive stress-amplitude without ever failing due to fatigue, which one would you choose. (See the attached figure) Q-2. What is the fatigue strength for the 1045 steel alloy, if you expect to...
number 17,18,19,20 material science 17. Pl astically deforming a metal specimen near room temperature generally leads...
number 17,18,19,20
material science
17. Pl astically deforming a metal specimen near room temperature generally leads to which of the following property changes? a. A decreased yielding strength and an increased ductility b. An increased yielding strength and an increased ductility c. A decreased yielding strength and a decreased ductility d. An increased yielding strength and a decreased ductility 18. A dislocation formed by adding an extra half-plane of atoms to a crystal is referred to as a (an) a....
Which of the following is not a strengthening method for crystalline metals? A. Hot-working B. Cold-working....
Which of the following is not a strengthening method for crystalline metals? A. Hot-working B. Cold-working. C. Grain refinement D. Interstitial alloy addition E. None of the above. These are all strengthening methods. A unidirecional composite of 35% by volume Eglans for in apocytsee Table 1)is subjected to a stress of 200 MPa parsial to the fore dinction. The strain in the comples Table 1 pdf 71 kn A 0070 0.000 C 728 OD. 0007 O E 0.004 Table 1...
need help with 4-9 4 which method is not used in processing an alimenam alley. (A)...
need help with 4-9
4 which method is not used in processing an alimenam alley. (A) spinning (6) setering c) forging (D) rolling (e) extrusion strengthening metals at low temperature requires Himpeding the motion of which crystal imperfection HCA) vacancy (8) interstial (c) dislocation co) grain boundary (6) void || If you cold work a brass which is not true (A) yield strongth is increased (1) tensile strength is increased (c) elastic modules is increised (o 7 Elongation is decreased...
1.1 Which of the following is NOT a combination of slip planes and slip directions of...
1.1 Which of the following is NOT a combination of slip planes and slip directions of FCC? (A) (111) [10i] (8) (111) (T10] 1.2 Which of the following best explains why FCC metals (Cu, Al, Ni, Ag, Au) are of higher ductility than HCP metals (Mg, Ti, Zn)? (A) Because FCC metals have more free electrons to move around and facilitate dislocation motion; (B) Because FCC metals have more number of slip systems (i.e. slip planes and slip directions) (C)...
reasons. a) Why might HSLA steel makers am to have dynamic recrystallisation dung the high temperature...
reasons. a) Why might HSLA steel makers am to have dynamic recrystallisation dung the high temperature rolling period and then to avoid static recrystallisation during the hold period? (1 mark) (1) Why are interstitial free steek relatively sof? (1 mark) b) Why might the folowing products have higher cold fomability than Dual Phase HSLA steek? Give your TRIP assisted steel (1 mark) Ferrite Pearlite HSLA steek. (1 mark) c) What is meant by the Dead Metal Zone in a flow...
Question 4 (25 marks) (a) Consider the hypothetical eutectic phase diagram for metal for lead-tin system....
Question 4 (25 marks) (a) Consider the hypothetical eutectic phase diagram for metal for lead-tin system. Assume that (1) A and B phase cutectic phase diagram for metals A and B, which is similar to that 1. Assume that (1) a and B phases exist at the A and B extremities of the phase diagram, respectively; (2) the eutectic composi m, respectively; (2) the eutectic composition is 36 wt% A-64 wt% B; and (3) the composition of the a phase...
1. Circle whether the following statements are true (T) or false (F). (2 mark each, total:...
1. Circle whether the following statements are true (T) or false (F). (2 mark each, total: 32) I F Substitutional atoms replace the solvent atoms in a unit cell F F Increasing grain size will increase the yield strength. F Growth of a phase is a thermally activated process. T F Spheroidizing results in coarse precipitates. TF Hot working requires less energy for plastic deformation than cold working F F A eutectoid reaction can be written as: Le Solid 1...
Use the following key words for part I: Forging Solid Solution Alloying Rolling Grain Size Reduction Strain Hardening Extrusion I- Among the given key words: a) (3) Provide ALL techniques for cold working. b) (5) Provide ALL methods for material strengthening. In one sentence, explain how all these methods provide material strengthening. c) (2) Which method provides material strengthening by increasing the grain boundary surface? d) (2) Which method provides material strengthening by increasing the amount impurity atoms? e) (2)...
Q-12. Which stage of the annealing of a cold worked metal causes the strength and grain size to decrease? (a) Grain growth (b) Recrystallization (c) Recovery Q-13. What is termed a "stress-relief anneal” is achieved as a result of (a) Recovery (b) Recrystallization (c) Grain growth Q-14. During recovery, we expect all of the following EXCEPT (a) Residual stresses to be reduced or eliminated (b) Electrical conductivity to increase (c) The anisotropic behavior caused by cold working to be eliminated...
Q-1. You are testing a circular beam of two metals, 1045 steel and 2014-T6 aluminum, in a rotating-cantilever beam fatigue test. If you need to choose one of these metals so that you can essentially design a part made of that metal, and subject the part to a repetitive stress-amplitude without ever failing due to fatigue, which one would you choose. (See the attached figure) Q-2. What is the fatigue strength for the 1045 steel alloy, if you expect to...
number 17,18,19,20
material science
17. Pl astically deforming a metal specimen near room temperature generally leads to which of the following property changes? a. A decreased yielding strength and an increased ductility b. An increased yielding strength and an increased ductility c. A decreased yielding strength and a decreased ductility d. An increased yielding strength and a decreased ductility 18. A dislocation formed by adding an extra half-plane of atoms to a crystal is referred to as a (an) a....
Which of the following is not a strengthening method for crystalline metals? A. Hot-working B. Cold-working. C. Grain refinement D. Interstitial alloy addition E. None of the above. These are all strengthening methods. A unidirecional composite of 35% by volume Eglans for in apocytsee Table 1)is subjected to a stress of 200 MPa parsial to the fore dinction. The strain in the comples Table 1 pdf 71 kn A 0070 0.000 C 728 OD. 0007 O E 0.004 Table 1...
need help with 4-9
4 which method is not used in processing an alimenam alley. (A) spinning (6) setering c) forging (D) rolling (e) extrusion strengthening metals at low temperature requires Himpeding the motion of which crystal imperfection HCA) vacancy (8) interstial (c) dislocation co) grain boundary (6) void || If you cold work a brass which is not true (A) yield strongth is increased (1) tensile strength is increased (c) elastic modules is increised (o 7 Elongation is decreased...
1.1 Which of the following is NOT a combination of slip planes and slip directions of FCC? (A) (111) [10i] (8) (111) (T10] 1.2 Which of the following best explains why FCC metals (Cu, Al, Ni, Ag, Au) are of higher ductility than HCP metals (Mg, Ti, Zn)? (A) Because FCC metals have more free electrons to move around and facilitate dislocation motion; (B) Because FCC metals have more number of slip systems (i.e. slip planes and slip directions) (C)...
reasons. a) Why might HSLA steel makers am to have dynamic recrystallisation dung the high temperature rolling period and then to avoid static recrystallisation during the hold period? (1 mark) (1) Why are interstitial free steek relatively sof? (1 mark) b) Why might the folowing products have higher cold fomability than Dual Phase HSLA steek? Give your TRIP assisted steel (1 mark) Ferrite Pearlite HSLA steek. (1 mark) c) What is meant by the Dead Metal Zone in a flow...
Question 4 (25 marks) (a) Consider the hypothetical eutectic phase diagram for metal for lead-tin system. Assume that (1) A and B phase cutectic phase diagram for metals A and B, which is similar to that 1. Assume that (1) a and B phases exist at the A and B extremities of the phase diagram, respectively; (2) the eutectic composi m, respectively; (2) the eutectic composition is 36 wt% A-64 wt% B; and (3) the composition of the a phase...
1. Circle whether the following statements are true (T) or false (F). (2 mark each, total: 32) I F Substitutional atoms replace the solvent atoms in a unit cell F F Increasing grain size will increase the yield strength. F Growth of a phase is a thermally activated process. T F Spheroidizing results in coarse precipitates. TF Hot working requires less energy for plastic deformation than cold working F F A eutectoid reaction can be written as: Le Solid 1...
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