Question

1. The pressure of a gas is increased by a factor of 5 and the temperature changes from 30 Kelvin to 200 Kelvin. What would have been the temperature if the pressure had only been tripled instead?

Answer 1

If pressure increased by a function of 5 so initial pressure = p_1 = p then final pressure p_2 = 5p T_1 = 30 k T_2 = 200 k If pressure is tripled then p_2 = 3p so p_2/T_2 = p_1/T_1 (from Gay lussac law) implies 3p/T_2 = p/30k implies 3p/p times 30k = T_2 implies 90k = T_2 Therefore Temperature would be 90 k