Benzene and toluene form nearly ideal solutions. If at 300K, P_ToI = 0.0422 atm and P_Benz*...

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Benzene and toluene form nearly ideal solutions. I

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Answer 1

Answer #1

(a) Assuming the solution is ideal, Raoult's law can be applied. Vapor pressure of a component in a solution in given by Raoult's Law

P_i = x_i.P*

P_i = Partial pressure of component i in the mixture, x_i = mole fraction of component i and P* = Vapour Pressure of pure component i.

Total vapour pressure of the solution is the sum of partial pressure of all the components in the solution.

P_total = P_benzene + P_toulene

P_total = x_benzene.P*_benzene + x_toulene.P*_toulene

(x_benzene = 1 - 0.6 = 0.4)

P_total = 0.4 x 0.136 + 0.6 x 0.0422 = 0.0544 + 0.02532 = 0.0797 atm $\approx$ 0.08 atm.

(b) Mole fraction of toulene in vapour phase = Vapour pressure of component / total vapour pressure

= 0.02532 / 0.0797 = 0.3176

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Answer 2

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