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Starting from rest, a 3.2-kg box is pushed on a horizontal floor with a force of...

Starting from rest, a 3.2-kg box is pushed on a horizontal floor with a force of 482.6 N parallel to the floor. The coefficient of kinetic friction between the box and the floor is 0.5. What is the kinetic energy of the box after it has been pushed with the constant force of 5.8 meters?

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Answer #1

here,

mass , m = 3.2 kg

force applied , F = 482.6 N

uk = 0.5

the kinetic energy of the box after it has been pushed with the constant force , KE = work done by force - work done by frictional force

KE = F * r - uk * m * g * r

KE = 482.6 * 5.8 - 0.5 * 3.2 * 9.81 * 5.8 J

KE = 2708.04J

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