[H+] [OH-] = 10-14
pH = - log [H+]
Part A
[OH-] = 2.7 x 10-7 M
[H+] = 10-14 / 2.7 x 10-7
[H+] = 3.7 x 10-8
pH = - log [3.7 x 10-8]
pH =7.43
Part B
[H3O+] = [H+] = 4.7 x 10-3 M
pH = - log [4.7 x 10-3 ]
pH = 2.32
Part C
[H3O+] = [H+] = 2 x 10-4 M
pH = - log [ 2 x 10-4 ]
pH = 3.69
Part D
[OH-] = 8.0 x 10-9 M
[H+] = 10-14 / 8.0 x 10-9
[H+] = 1.25 x 10 -8
pH = - log [ 1.25 x 10 -8 ]
pH = 7.9
Determine the pH for the following solutions: Part A [OH-] = 2.7x10-7M Express your answer using...
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