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The pH of a cup of coffee is 5.06. Calculate the concentration of H3O+ and OH in the coffee. (Enter your answer to two signif
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Solution : from relation, pH = -log sezot) or seg 0+2 = 10 P4 given, P4 = 3.06 Hence, s azot) = 10 (56) (120) = 8.7X10M since

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