
![5 moles of CS₂ = 336 mo. = 0.672 theoretical field of CS = moles of cha) x (moleccter weight of cs]} Theoretical yield = 0.67](http://img.homeworklib.com/questions/d7efddf0-d66b-11ea-ac1d-c36819d91ddc.png?x-oss-process=image/resize,w_560)


Carbon disulfide is produced by the reaction of carbon and sulfur dioxide. 5C(s) + 280,(9)-CS (9)...
Carbon disulfide and carbon monoxide are produced when carbon is heated with sulfur dioxide. 5C(s)+2SO2(g)→CS2(l)+4CO(g) Question: How many moles of CO are produced when 1.5 moles C reacts? Express your answer using two significant figures.
When carbon disulfide reacts with chlorine, carbon tetrachloride and sulfur dichloride are produced. The balanced equation for this reaction is: CS2(s)+ 4C12 (8) CC4()+2SCI (s) If 16 moles of chlorine react, The reaction consumes moles of carbon disulfide. The reaction produces moles of carbon tetrachloride and moles of sulfur dichloride.
Submit Request Answer Part B What is the percent yield of carbon dioxide i the reaction of 73.1 g of carbon monoxide produces 86 2 g of carbon dioxide? Express your answer to three significant figures. CO2 Submit
Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is S,(g) + C(s) = CS, (g) Kc = 9.40 at 900 K How many grams of CS2(g) can be prepared by heating 11.8 mol S2(g) with excess carbon in a 6.15 L reaction vessel held at 900 K until equilibrium is attained? mass of CS2(g): 09
1. For the following reaction, 5.47 grams of oxygen gas are mixed with excess sulfur dioxide . The reaction yields 19.3 grams of sulfur trioxide . sulfur dioxide ( g ) + oxygen ( g ) sulfur trioxide ( g ) What is the theoretical yield of sulfur trioxide ? grams What is the percent yield for this reaction ? % 2. For the following reaction, 6.54 grams of chlorine gas are mixed with excess carbon disulfide. The reaction yields 3.11...
Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is S2(g) + C(s) = CS, (g) Kc = 9.40 at 900 K How many grams of CS2(g) can be prepared by heating 11.4 mol S2(g) with excess carbon in a 5.15 L reaction vessel held at 900 K until equilibrium is attained? mass of CS2(g): bun
Carbon disulfide gas and oxygen gas react to form sulfur dioxide gas and carbon dioxide gas. What volume of sulfur dioxide would be produced by this reaction if 9.5 mL of carbon disulfide were consumed? Also, be sure your answer has a unit symbol, and is rounded to 2 significant digits.
Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is S2(g)+C(s)−⇀↽−CS2(g) Kc=9.40 at 900 How many grams of CS2(g) can be prepared by heating 11.5 mol S2(g) with excess carbon in a 5.65 L reaction vessel held at 900 K until equilibrium is attained?
Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is S2(g) + C(s) = CS (8) K. = 9.40 at 900 K How many grams of CS2(g) can be prepared by heating 17.9 mol S2(g) with excess carbon in a 7.90 L reaction vessel held at 900 K until equilibrium is attained?
Carbon disulfide is prepared by heating sulfur and charcoal. The
chemical equation is
How many grams of CS2(g) can be prepared by heating 10.8 moles
of S2(g) with excess carbon in a 5.30 L reaction vessel held at 900
K until equilibrium is attained?
rbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is 9.40 at 900 K CS How many grams of g) can be prepared by heating 10.8 moles of S2(g) with excess carbon in...