Question

Calculate the mass of butane needed to produce 87.6 g of carbon dioxide.

Answer 1

Sol) To solve these kind of problems, first write balanced reaction, 2 Cu H10 + 13028 CO2 + 10H₂O where Cu HiO = Butane O₂ = oxygen CO2 = Carbon dioxide H₂O = water. It is given that 876 g of carbon is produced Obtain molar mass of CO2 from the book, modlar mass CO2 = 44 glmal Given mass of co2 = 87.6 g moles of CO₂= Given mass = 876 g =1-99 gnoles Molar mass from the reach'on, 2 moles of Cu Hio react with 13 moks of Oz to form & moles of coz and 10 moles of H₂O. > 2 moles of Cy Hio will lead to formation of 8 moles of CO₂ Reversly, & moles of CO₂ will be produced by 2 moles Cylio - 1.99 moles of CO2 will require = 1.99x2 = 0.497 moles 8 of Culio molar mass of Cu Hio = 58112 glmole we know moles = mass 0.497 moles= mass 58:12g/mole mass= 28.88 g of butane) molar mass