In another version of the "Giant Swing", the seat is connectedto two cables as shown...

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In another version of the "Giant Swing", the seat is connectedto two cables as shown...

In another version of the "Giant Swing", the seat is connected to two cables as shown in the figure (Figure 1) , one of which is horizontal. The seat swings in a horizontal circle at a rate of 30.9 rev/min

Part A

If the seat weighs 220N and a 829-N person is sitting in it, find the tension in the horizontal cable.

Part B

If the seat weighs 220N and a 829-N person is sitting in it, find the tension in the inclined cable.

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Answer 1

Answer #1

W = T2 cos 40 since only T2 has a vertical component
T2 = (220 + 829) / cos 40 = 1370 N
T2 sin 40 + T1 = m v^2 / R = m w^2 R where w is angular velocity
T1 = 1370 sin 40 + (1049 / 9.8) * w^2 * 7.5
T1 = 881 + 803 * w^2
w = 2 / 60 * 2 * pi = .209 rad / sec
T1 = 881 + 168 = 1049 N

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Answer 2

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