Question

tically upward. 60.0° position and me. (b) What is 45.0 cm/s 0 for the first 1.06 m inarian with m above the shoots hori- ee in a vain muzzle ve- e the mon 8.75 m . Kicking an Extra Point. In Canadian football, chdown the team has the opportunity to earn one more goal posts. The 3.58 kicking the ball over the bar between the o ft above the ground, and the ball is kicked from ground ft horizontally from the bar (Fig. P3.58). Football re stated in English units, but convert them to SI u blem. (a) There is a minimum angle above the grou rise up- tio iral-like. 3.53 The Longest Home Run. According to Guinness Worl on com Records, the longest home run ever measured was hit by Roy "Di that if the ball is launched below this angle, it can never r no matter how fast it is kicked. What is this angle? d com- Carlyle in a minor league game. The ball traveled 188 m (6 ally at before landing on the ground outside the ballpark. (a) If the ball's 18 ft) hall is kicked at 45.0° above the horizontal, what must speed be if it is just to clear the bar? Express your ansv and in km/h.

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Answer 1

a)This is a question of projectile motion.

As this question demands no significance of time it is just using coordinates so we can use equation of trajectory of projectile motion which is

y= x*$tan\Theta$ - (g x² /2 v $cos$²$\Theta$)

here y=0.9

$\Theta$=45 degrees

g=9.8m/s²

x= 188

so

0.9=188*1 - (9.8*188²/2*v*(1/2))

solving this we get v=1851.26 m/s

b) In this part we will again use same equation and find height=y from the given condition

y= 116*1- 9.8*116²/(2*1851.26*(1/2))

y=116-71.23

y=44.76m

now height of fence is 3m

so height of ball from fence is 44.76-3=41.76m