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The total length of the piping system made of cast iron providing hot water to a house is considered to have a 42m length wit
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a) Datas given The required flow rate is given by, Q=0.1 lit/s Q=0.1*10- m/s = 0.0001m/s L = 42 m Velocity of the flow is gi0.000127 980x -XD Re= D2 1.138x10- 109.65 Re: D Relative roughness is given by, Esteel = 0.26 mm € 0.00026 = D D To find frich₂ = hgthm fLV? +0 2gd 0.000127 fx42 D4 D 2x 9.81 3.45269x108xf h; PzV +2, +h; By applying Bernoullis theorem P. ² + +Z2 +hp0.000127 V= (0.012) V = 0.882 m/s To find friction factor, = --1.8log 10 2.454x10-5 01:11 + 6.9D 109.65 -1.8log 10 2.454x10-5D=12 mm S.NO d (in mm) d (in m) V (m/s) 1/(f)^0.5 f D D (in mm) 1 11 0.011 1.049587 4.249646 0.055373 0.01213 12.12976 2 11.2b) The required flow rate is given by, Q=1 lit/s Q=1x10- m/s = 0.001m/s L = 42 m Velocity of the flow is given by, Q = AV V=Relative roughness is given by, Esteel = 0.26 mm E 0.00026 = 0.0086 D 0.03 To find friction factor using Colebrook equation,4*Threaded unions, K=0.08 Note: The loss coefficient values will differ according to various textbooks. Minor loss coefficien(85–15)x103 (1.415) +h; = 1.05 +5.7043m 980x 9.81 2 x 9.81 7.281+hp = 5.8114m hp = 1.4695 m Pump Power is given by, P PgQh, n

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