Question

Topic: Compressible fluid flow

Carbon dioxide gas (μ=1.5x10^-5 N-s/m² ) flows in a horizontal 30-mm wrought iron pipeline at a speed of 8 m/s. At a point in the line a P gauge=690 kPa and the temperature is 40⁰C. What P is lost as a result of friction in 50 m of this pipe? P_barometric = 101.3 kPa. Check if Weymount equation can be used and utilize it if possible.

Answer 1

Page 1 Peacsek Page No. Date 8 7 7 Given, On S 30 mm 50 2 het hun P2 Mco = 105x10s Nors/m² v= flow in pipe = 8 m/s dpipe Ipipe = Pgauge = 690 kPa = pi P2 = ? (find out) Now, steady state Energy Equation Pi-P2 4 Zi-Z2 = S21X8802g Horizontal pipe → elevation No change in velocity, Vi= V2 hf - Major friction loss hm = Minor loss to (neglected) = specific gravity of CO2 = 1.55 Pi-P2 A hf FL v स f = friction factor ago If = 64 Re and (leo, 1.98 kg/m?) Re f = 64 Zi= Z2 S hf S 2 f = 64 Re SVD SND hf = 648(Lv from ear o 64X(Lv) x M (ND) x 128D) 64 MLV Sg D2 2

Page 2 Peacock Page No. Date he - x 50 x 8 32X1.5X105 1.98 x 9.81 X (3x16222 hg = 10.983 from egy A ht S 01 Pi-P2 = hf У P2 = P- hfos (690 10.983x1.55*103) KPg P2 = 689.98 kla x 100 Pressure Drop (%) = P.-P2 Pi-Palm 696-689.98 690 10663 xls So, me pressure Drop < yo oro Darcy - weisbach flow equation No need to use weymount equation, ure