Question

The equilibrium constant, K, for the following reaction is 6.30 at 723K. 2NH3(g) N2(g) + 3H2(g) If an equilibrium mixture of the three gases in a 10.1 L container at 723K contains 0.410 mol of NH3(g) and 0.250 mol of N2, the equilibrium concentration of Hy is M.

Answer 1

We know the equilibrium constant (Kc) for a reaction at equilibrium is the ratio between the product of concentration of products, each raised to the power of their number of moles involved to the product of concentration of reactants, each raised to the power of their number of moles, present at equilibrium  

I.e for the given reaction-

3 2 大。 A. J x DE) | Mars] 1 6-b = (0.02kg) - BJ? {o.st)? 1 DR.J - 6 34 ~ (0.6476) 2 6 0.0NY 37 0.41 (%) 1.) - Jo-Y19 [Hg) - 0.748 m