Question

Question 7 of 14 > The table lists the specific heat values for brick, ethanol, and wood. Specific Heats of Substances Substance Brick Ethanol Wood Specific Heat 0.20 0.58 0.10 Calculate the amount of heat, in calories, that must be added to warm 37.1 g of brick from 19.4°C to 44.6 °C. Assume no changes in state occur during this change in temperature. heat added

Answer 1

Solution ogiven: - mass of brick Specific Heat 37.1 g 0,20 cal 9 °C Tinitial 19, 4°C final = 44.6 °C Therefore AT= 44.60€ -19.4°c 25.20 °C Calculate, the heat transfer using this equation ! - Q (м x сx ДТ Where Heat taansfer. M2 mass specific Heart Temperertiae change. OTT

putting the values in this equations = 37.19% 0.20 cal x 25.20€ goc cal V = 186.98 Hence, heart added = 186.98 cal given: . mass of ethanal 37.1 g 0.58 Cal g oc 25.2°C OT44.6°C -19.4°C Therefore, = Meat

9- 37.18 X 0.58 cal X 25. 20°C 8.4 542.25 cal Hence, 542.25 Heat added • given: - wood = 37.19 CE 0.10 041/9c 25. 20°C AT: 44.6°C - 19.40 Therefore, De M.GOTI Q 371.1 x 0,10 cal Gi x 25.20€ C 93.49 GI Hence, The required heat is 93.49 CH

• The goeatest heat requlaed for ethanel is 542.25 CM)