Question

QUESTION 3 2 marks Suppose the following declarations appear in the nai nfunction of a C++ program: string nane, course, date; float cost; bool approved; Suppose the following calling statement appears in the nai nfunction: approveFunds("Menory enhancement", "Ell en Subi sa", date, 595.00, approved): Which of the options below is a correct function header of the function approveFunds in the main function? 1. void approveFunds(string coursep, string namep, string & dat ep, float cost P, bool & approved) 2. void approveFunds(string & coursep, string & nane, string dat eP, float & cost P, bool approvedP) 3. voi d approveFunds course, nane, dat e, cost, approved) 4. void approveFunds "Merror y enhancement", "El I en Subi sa", date, cost, approved) QUESTION 4 2 marks Which of the options below expresses the logic that neither of the following two statements are true? i is less than 4 ori is greater than 10, and i times is greater than 54. 1. (!((i <4 2: 8:{{4|| 1 318354 3. ((i < 411 1 > 10) || (i j > 54) ) 4. (!((i < 4 && i > 10) && (i'j > 54) ) ) [TURN OVER] COS1511 MAY/JUNE2020 QUESTION 5 2 marks Which of the options below expresses the logic that a person is ready if they are either not wearing jeans or they are wearing a hat and bronx shoes? 1. ready = clothing != "jeans" || hat == 'y' & shoes == "bronx"; 2. ready = clothing != "jeans" && hat == y" || shoes == "bronx"; 3. ready = clothing != "jeans" || hat == 'y' || shoes == "bronx 4. ready = clothing != "jeans" && (hat == 'y' && shoes == " bronx");

Answer 1

Answers:

Question 3: option 1 is Correct.

1. void approveFunds( string courseP, string nameP, string & dateP, float costP, bool approvedP )

--> The 3rd and 4th options are wrong because they do not contain the data-type in the header

--> The 2nd option is wrong because it is using the addresses for course, name, and cost but the calling statement in the main function is not passing the addresses for those variables.

-->Option 1 is following the according to the calling statements and has data-types in the header. Hence, it is the correct function.

Question 4: option 2 is Correct.

2. ( !( ( i < 4 || i > 10 ) || ( i * j > 54 ) ) )

--> statement 1 :- i < 4 || i > 10

statement 2 :- i * j > 54 from the question neither should be true which means both statement 1 and statement 2 are false.

Hence, !( i < 4 || i > 10 ) and !( i * j > 54 )

--> !( i < 4 || i > 10 ) && !( i * j > 54 )

--> !( ( i < 4 || i > 10 ) || ( i * j > 54 ) )

when we take both negations ( ! ) common, and (&&) becomes or ( || ).

hence, ( !( ( i < 4 || i > 10 ) || ( i * j > 54 ) ) ).

Question 5: option 1 is Correct.

1. ready = clothing != "jeans" || hat == 'y' && shoes == "bronx";

-->Statement is not wearing jeans or wearing hat and bronx shoes.

--> !(jeans) or (hat and bronx shoes)

--> (clothing != "jeans" ) || ( hat == ''y' && shoes == "bronx" ) since && has higher precedence than ||, we drop the parenthesis.

-->  clothing != "jeans" || hat == ''y' && shoes == "bronx"

--> hence, ready = clothing != "jeans" || hat == ''y' && shoes == "bronx" ;