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(1) Show that if H ≤ Sn, then exactly one of the following two cases holds:...

(1) Show that if H ≤ Sn, then exactly one of the following two cases holds:

(a) All elements of H are even.

(b) The number of even permutations of H is the same as that of odd permutations of H.

(2) Show that if (Sn : H) = 2, then H = An

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Answer #1

of Sn. subgroup only even permutation se all let H < Son be in be is be a If it contains no odd permutations, then it contain

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