Question

4.3 Assume that values have been assigned to all the elements of playland play2. Also assume that an int variable trickyhas been declared and intialised to 0. Use nested forloops and write down the necessary C++ statements to do the following: Each row of playlis compared element by element to the corresponding row of play2. If the elements are equal, add the value of one element to tricky. If the elements are not equal, add the sum of the two elements to the value of tricky. For example, if playl and play2 are initialised as follows: and 1 5 6 8 3 3 7 8 3 5 3 1 7 8 5 5 4 6 5 0 8 7 7 3 3 7 6 4 7 8 5 5 respectively, then the value of tricky will be: 5+11+3+7+11+8+12+8+11+10+9+5+7+11+5+5=128 Display the value of tricky. Do NOT write a complete program or any functions. Write down ONLY the required statements. (8)

Answer 1

//The required code with asked statements:

#include <bits/stdc++.h>
using namespace std;

int main(){
   int n,i,j,k;
   cin>>n;
   int play1[n][n],play2[n][n],tricky=0;
   for(i=0;i<n;i++){
       for(j=0;j<n;j++){
           cin>>play1[i][j];
       }
   }
   for(i=0;i<n;i++){
       for(j=0;j<n;j++){
           cin>>play2[i][j];
       }
   }

   //this is start of the the required statements
       for(j=0;j<n;j++){
           for(k=0;k<n;k++){
               if(play1[j][k]==play2[j][k]){
                   tricky+=play1[j][k];
               }else{
                   tricky+=play1[j][k]+play2[j][k];
               }
           }
       }
   //end of required statements
  
   cout<<tricky;

}

#include <bits/stdc++.h> using namespace std; int main(){ int n,i,j,k; cin>>n; int play1[n][n],play2[n][n], tricky=0; for(i=0;i<n;i++) { for(j=0; j<n; j++){ cin>>play1[i][j]; } ها for(i=0;i<n;i++){ for(j=0; j<n; j++){ cin>>play2[i][j]; 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 } ہا //this is start of the the required statements for(j=0; j<n; j++){ for(k=0;k<n;k++){ if(play1[j][k]==play2[j][k]){ tricky+=play1[j][k]; }else{ tricky+=play1[j][k]+play2[j][k]; } } } //end of required statements cout<<tricky; 32

//Output

4 1 5 3 7 6 8 5 8 3 3 3 5 7 8 1 5 4 6 3 7 5 0 7 8 8 7 6 5 7 3 4 5 128 ... Program finished with exit code 0 Press ENTER to exit console.

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