Question

An electron (mmm = 9.11×10⁻³¹ kg) is accelerated from rest to speed v by a conservative force. In this process, its potential energy decreases by 8.50×10⁻¹⁴ J.

Determine the electron's speed, v.

Answer 1

Solution Kinetic energy in this m Note that the I mu? formula mass is assumed to be constart, and K iu called Newtonian K.E. However, in Albert Einstein's relativity theory mass 'mi increases with velocity and Kinetic energy K.E. is given by the formula- the - K.E. moe² (VIC)² where zero. mass of the particle when it's velocity и speed of light. called relativistic This kinetic energy. Since decrease in P.E. increase in K.E. K. Ef - KEO K.E K. above 8.500 1014 s Plug the giver values in formular 8.50 x 10-14 (9.11x1031) ( 3x108j? x Vi-cu/3x10872 = 2.61 x 108 mis Ane = 2.61 x 108 0.870c 3 X 108 OY

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