In an Arithmetic Sequence the difference between one term and the next is a constant.
In general we could write an arithmetic sequence as-: {a, a+d, a+2d,........}
where:
In the given question, we have sequence as -: -1, 1, 3 ..............
so, here a = -1 (first term)
and d= (second term -first term) 1-(-1) = 2 = (third term - second term) = (3-1) = 2
Therefore, in this question d = 2 (common difference)
nth term of an arithmetic sequence is given by: an = a+((n-1)*d)
Therefore, 80th term of above arithmetic sequence would be given by-:
a80 = a+(80-1)*d = -1+(79*2) = 157
80th term of this arithmetic sequence is = 157
Write an equation for the n th term of the arithmetic sequence.
Then find a50.
1/3, 1/2, 2/3, 5/6
Use the formula for the general term (the nth term) of an arithmetic sequence to find the indicated term of the sequence with the given first term, a, and common difference, d Find a1so when a,-50, d-5 a1s0"
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