Question

solve the triange. Round to nearest tenth or nearest minute B = 53.2° C=100.6° b = 31.5

Answer 1

​​​​​​.

A since sum of all thosee intanion angles of a triangle is 180°, so we have, 180°- (53.2° + 100.60) 26.2 Now by sine low, we have La C Sin A b sin B sin e a a Sin (26-2°) 117.4 Now, 31.5 sin 63-29 sin (100.6°) 31.5 sin (26.2°) sin (53.2%) => a = 31.5% sin (53.2) 31.5 Exe=31.5% sin (100.6%) Sin (53.20) sin (53.2) son (26-2) 38.7 Again, sin (108.6)

.

So we have,

A = 26.2°

a ≈ 17.4​​​ (rounded to nearest tenth)

c ≈ 38.7​​​ (rounded to nearest tenth)