Question

I have a 1.3 kg block of ice that I pull out of the freezer. That block of ice is initially at a temperature of -20 °C . How much heat is required for this block of ice to turn into 1.3 kg of liquid water at 20 °C.

Answer 1

Given,

Mass of the block of ice, $m=1.3kg$

Initial temperature, $T_i=-20\degree C$

Final temperature, $T_f=20\degree C$

We know that specific heat capacity of ice,

Latent heat of fusion of ice,
1 = 3.36 * 10 Jkg-1

Specific heat capacity of water,  

Heat required for the ice to reach $0\degree C$ ,

  $Q_1 = mC_i\Delta T$

  

  

Heat required to convert it from ice to water,

  

  

  

Heat required for water to reach $20\degree C$ ,

  $Q_3=mC_w\Delta T$

  $Q_3=1.3*4.2*10^3*(20-0)$

  $Q_3=109200J$

Total heat required,