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Question 6 Your answer is partially correct. Try again. A 25.0 kg satellite has a circular orbit with a period of 4.10 h and

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Given time period= T = 4.1 h=14760 s The mass is 472 T2 = R GM 412 (14760) = (4.90x109) (6.67x10-4)M M = 3.196x10 kg The radi

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