Question

Please answer all 3 questions

17 1 The figure to the right shows two long, straight, current carrying wires, as well as a circular, current carrying loop of wire. If the currents listed have values of 1 = 3.30 A, I2 = 2.50 A, and 13 = 1.40 A, and the distance values listed are n = 18.0 cm, r2 = 16.0 cm, and r3 = 11.0 cm, what is the magnetic field, magnitude and direction, at the center of the loop? х 1 Z Magnetic fields can exert forces on moving electric charges, but they cannot change the speed of these charges. What is the physical significance of this fact? a) Magnetic forces cannot accelerate the charges. b) Magnetic forces cannot change the momentum of the charges. c) Magnetic forces cannot do any work on the charges. d) Magnetic forces cannot alter the trajectory of the charges. The figure shows the motion of electrons in a wire which is near the N pole of a permanent magnet. The wire will be pushed N Electron Flow

Answer 1

I, = 3:30 A, I, = 2.50 A, I2 = 1.40 A 7,-0.18m, , 0.160m, 73 - 0-1/ m . I, e X 6. : 3. 67x10 °7 along 250, 2nx 0-18 2 T X 0.16 2x Orll T along tz Magnetic field at the centre o of the loop due to current Is is B, = Mo II 45 x 10 x 9.30 → B, = 3 Magnetic field at o due to current hy is Be a lo ļ B, 4x10lx. 1x 2.50 = B₂ = 3-12x156 T along +2 Magnetic field at o due to the current Ig is Be = po Is 28g By = Arx107x1.40 =) B₂ = 8.00x10° T along tz Total magnetic field at the centre of the loop, B = B:+D3 - 8, B = (3.12 + $ – 3-67 ) x1706 = 7.36 2106 The net magnetic field at the centre of the loop, B=7.36x10 Coupe and its direction is along tre z-axis Magnetic force on a charge moving through a magnetic field B is ² = q ( V x 8). The direction of ² is perpendicular to the kelocity v and hence work done is ZERO. ... The speed of a charge moving through a magnetic field remains the same (1) Magnetic forces cannot do any work on the charges. 3. The flow of election in the wire constitule an electric current along -y-ari Magnetic field of the magnet is al mg +ve xax's Fore on the wire, P = (52(-9) * Bc+?')) - TLB (-3x 2) ILA (R) 2. The wire will be pushed along the Zhxis