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The intensity of solar radiation that falls on a detector on Earth is 1.00 kW/m2. The detector is a square that measures 6.11
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Find the power absorbed using intensity and area and use that to find the time required to measure the given energy as shown below[ = 1000 w/v2 Power absorbed ریا P= I Acoso (1000 w/22 (611) 2 os30 = ا 32335.5 t = E حال c 448x1027 32330 $ w - و 30 13

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