Question

please answer my question. and put answer in bold or in a box. explain

1. [-/2 points) DETAILS SERCPWA11 6.WA.022. TUTORIAL. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER As shown in the figure below, a bullet is fired at and passes through a piece of target paper suspended by a massless string. The bullet has a mass m, a speed for the collision with the target, and a speod (0.506)v after passing through the target. The collision is inelastic and during the collision, the amount of energy lost is equal to a fraction ((0.443)KE c) of the kinetic energy of the bullet before the colon. Dette mass M of the target and the speed of the target the instant after the collision in terms of the mass of the bullet and speed of the built before the compress you to at least 3 decimals.) V M Tutorial

Answer 1

solir using conservation of momentum speed (0.506) Givena (0.443 KEBC) Initial momentuma Final momentum mut M(O) MV + ml o:SALV) MV: vacia For 0.4aymo In elastic Collision using conservation q total energy system žmozte os mio!? - fm (osoby)* m02710-443) amuz MU? 1. 146 m2 -(2) in ean do in can Q) mv= 0.494 put (0.494mu /,u2 = 10146002 0:499 Ni 1.146v VO 2.3 kg • using egness M (2.3170) -0.494 myy Ang Now G. 209m Ang