Question

1.Mojave is driving his 1,598 kg Corvette on the 405 when he approaches his exit. If the exit has a radius of curvature 35 m and road is dry (coefficient of friction is 0.98) what is the fastest Mojave can safely take the turn?

2.Alyssa loves taking her 2,200 kg Land Rover Discovery off roading. After running it through a river at 35 m/s Alyssa has so much fun she decides to go back and do it again. If the coefficient of friction between Alyssa's tires and the grass is 0.65, what is the smallest u-turn (radius of curvature) Alyssa can use to go back to the river?

Answer 1

1 We know v Jurg V LJ velocity H= Coefficient of friction R= Radius => 0.98x 35 x 9.8 Tv = 18.334 m/ ga Acceleration 9.8 m/s ? due to gravity 2 IN using the same formula 35 < 10.65+ Kx 9.8 -> F R = 192.307 m