Question

A ray of light travels from air into another medium, making an angle of θ1 = 45.0° with the normal as in the figure below.(a) Find the angle of refraction θ2 if the second medium is fluorite.

°

(b) Find the angle of refraction θ2 if the second medium is water.

°

(c) Find the angle of refraction θ2 if the second medium is benzene.

Answer 1

n. Griven: A Ray of Light toavels from air into another medium. 01 = 45.0° = Incident angle O₂ = Refractive angle By using snell's law of Refraction ni 0 n sin Q4 n = Refractive Index of medium 1 (e. of air-c.e. In=1 п, Refractive Index of medium 2 le of oliven mediums sin Q2 Heye = Now (a) Q4 45.0', n,= 1 No = Refractive index of fluorite =h, 1433 from ean (1) sin Q₂ sin u5° CS Scannej. 4133 CamScanner

sino 1-433 0.707 sin Q2 = 0.43333 Q. = sin(0-4933) Therefore O2 = 29.55° 6 Given Og 45.0°, =1 Refractive Index for water is 1-333 į e. ne = 1.333 Applying snell's law of refraction. sin Oz sin 45.0° 1.333 sin Q2 1.333 0.707 sin or 0.5303 = Q2 sint (0.5303) Or 32.02° CS Scanned with Cam Scanner

(c = ? n=1 for air ņ= 1.501 for benzene Q, 45.0° O2 Using Snell's law of refraction. ni sinai sin Q2 1. 501 sin (45.0°) sin Oz Hz 1 - Ź 1501 sin Oz 1-501 0.707 sin Q2 = OoU710 O2 = sin" (0.4710) 28.09° z = CS Scanned with CamScanner