Question

Constants Two metal disks, one with radius Ri = 2.44 cm and mass M = 0.820 kg and the other with radius R2 = 5.07 cm and mass M2 = 1.66 kg, are welded together and mounted on a frictionless axis through their common center. (Figure 1). Part A What is the total moment of inertia of the two disks? I = 2.38 10-3 kg. m² Submit Previous Answers Correct Part B A light string is wrapped around the edge of the smaller disk, and a 1.50-kg block, suspended from the free end of the string. If the block is released from rest at a distance of 2.08 m above the floor, what is its speed just before it strikes the floor? IVO ALO ? m/s Submit Request Answer Part Repeat the calculation of part B, this time with the string wrapped around the edge of the larger disk. ΟΙ ΑΣφ ? Figure m/s < 1 of 1 > Submit Request Answer Provide Feedback Next > 1.50 kg

Answer 1

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I = 2.38 x13 kg-m² B) m= liskg h=2.08m, V=8 =) TX R1 = I (a てこIX T= 2.38x10²a = 3.9976 a (2.44 X13)? from 4, my-T-ma 7 1.5x9.8=1.50 +3.9976 a a= acceleration of m= 2.6739 m sec? Vc017 2ah = 2X2.6739X 2.08 =) v = 3.33518 m/sec And (Speed) if wrapped around outer loop, T=1&' - TX R₂ = I T = (2.38x103 Ja' 0.9258gal fin and too from @22, 1-579:8 = (1-5+0.92.589) = a' = 6.0596 m/sec2 Iv' =f(0°+2x 6.0596%2:08 (5:07x132) mg - I'=ma' 5.021 m/sec. Amuer