A soccer ball is resting on flat ground 8 meters away from a vertical wall. The ball is then kicked at an angle of 34.0 degrees with initial speed 10.0 m/s. When the ball strikes the wall, how far above the ground is it?
Motion along horizontal
d = v cos x * t
8 = 10 cos 34 * t
t = 0.965 sec
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Vertical height at this instant
H = (v sin x) t - 0.5 gt^2
H = (10 sin 34)* 0.965 - 4.9 *0.965^2
H = 0.83 m
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