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Ha 120-W lightbulb emits 2.5% of the input energy as visible light (average wavelength 560 nm) uniformly in all directions Pa
please answer part B - thanks!
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Solution Here P= 2.5 100 x 120 - 3 581 B so 3181 4 mx (1•0x103)? 2.39 X 10 7 J/sm2 Now the power entering to the eye Peye 나 X

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