Question

length d. THE ROD SHOWN is uniform and hass mass m and AXIS 1 passes through the midpoint of the rod Axis 2 Passes through Point B.A Small block of Mass attached the lept rod. The distance from axis 1 to 2 is the distance from axis 2. to axis 3 is 2m is axis end of Įd, and Id. Part 1: Find the moment of interia of rod about axis 1. + 2 m 12 3 mel I, E? ad 5 3 d Part 2 & Find the of moment morator of about axis inter ia 2 the rod Iz - ? Part3 Find of He of the interia moment rod about axis 3

Answer 1

Solution:

Ans:

Part 1: The moment of inertia of the rod-block system about axis 1 is $\frac{7md^2}{12}$ .

Given, length of of the rod d MASS the rod = the block - 2m MASS d 2m /2 K 4/6 d/3 242 - 21 3 rod about the pasts: The moment of chestia of the axis I given Md ² by Irod 12 The axis moment of westia of the mestia of the block about the by, nd 1 is given I block - 20 x m()* = md 2 Thus, the axis 4 moment of inertia of the system about given by, I - Isod + [block &nd² md² 12 + md 12

Part 2: The moment of inertia of the rod-block system about axis 2 is $md^2$

Part 3: The moment of inertia of the system about axis 3 is $\frac{7md^2}{3}$