Question

There is a 292 m high diff at Half Dome in Yosemite National Park in California. Suppose a boulder breaks toone from the top of this com (a) How fast (in m/s) will it be going when strikes the ground? (No Response) m/s (b) Assuming a reaction time of 0.175 s, how long (ins) will a tourist at the bottom have to get out of the way after hearing the sound of the rock breaking loose (neglecting the height of the tourist, which would become negligible anyway if hit)? The speed of sound is 335 m/s on the day (No Response)

Answer 1

solth. - birven "=292m g = 9.81 on 15² 9,-292m dR=0.1752 calculations : 0 According to kinematic equation of motion Tourist V = Va+2 (9) (9) VB=Jot +269.81)(292) [B= 75.69 mis First the time ts taken by the sound to reach the tourist given by = Vots tets 2922 335&st 4.905 ts? 4.905#+335545-29250 ts= 0.76 € According to kinematic equation of motion we know TAB is given by the equation, 9,= (VA) (IAB)+1(g) (HARİ 2 tape 292x2 AB= 7.72 & The tourist will hearre the rock cefter the sound reached and tr= 0.17ss so we can conclude that the time required for him to escape de is given by de=FAB-traits de = 7.72 - 0.175-0.76 de = 6785 S. at Hope This help. Thanks.