Question

im having a difficult time understanding this question could someone show their work along with the solution?

As shown in the figure below, a stick of length L -0.420 m and mass m = 0.200 kg is in contact with a rough floor at one end and a frictionless bowling ball (diameter d - 16.00 cm) at some other point such that the angle between the stick and the floor is - 30°. Determine the following 300 (a) magnitude of the force exerted on the stick by the bowling ball N Enter a number (b) horizontal component of the force exerted on the stick by the floor (c) vertical component of the force exerted on the stick by the floor

Answer 1

free body diagram mg Uv AB 730 IST А L-0.4204 M = 0.2 kg d = 16 con = a.lby a b = 2 / 2 = 2 zoofy from gle ABO thu = tanis tauls = 0.08 Ау 60330) @ for equilibrium EMATO AB=0.298 m ng (1 220330) = R(AB) = 0.2 (5.91) (6:40 C0520) -R (0.298) - 2= 1,197 N force enevled on on stick by ball & Fx=0 Ax- R sino=0 Ax-1.197 sinzito reaction by floor An= 0.598 N horizontal weaponent of O EFyzo Ay-ng+ R2013070 AY-0.2(9.81) + 1.197 cos3050 Ay=ON 0.925 Vertical reaction by flor.